4y^2+11y+3=0

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Solution for 4y^2+11y+3=0 equation: 



4y^2+11y+3=0

a = 4; b = 11; c = +3;
Δ = b2-4ac
Δ = 112-4·4·3
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{73}}{2*4}=\frac{-11-\sqrt{73}}{8}
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{73}}{2*4}=\frac{-11+\sqrt{73}}{8}
$

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